5x^2-7x-48=4

Solution for 5x^2-7x-48=4 equation:

5x^2-7x-48=4

We move all terms to the left:

5x^2-7x-48-(4)=0

We add all the numbers together, and all the variables

5x^2-7x-52=0

a = 5; b = -7; c = -52;
Δ = b2-4ac
Δ = -72-4·5·(-52)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-33}{2*5}=\frac{-26}{10}
=-2+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+33}{2*5}=\frac{40}{10}
=4
$